Question

python

Problem 3-6 points First, start with the following code: import numpy as np A np.random. randint (0, 10, sie n,n)) np. savetxt ('exam2.txt', A, fmt-idelimiter B-# np. zeros ( (n, n) , dtypes, int 64, ) When run, it will produce a file named "exam2.txt" that has 5 rows each with 5 numbers separated by commas,. In addition, a 5 by 5 array of zeros named B is defined. Run this code, but do not change it Your job is to do the following: 1, (3 points) Read the file using text procesing (think f open ( , exam2. txt , ) ), and put = each number of the file in the correct lócation in B. A and B should have identical values. If you get stuck, use the text loader from numpy for partial credit; if that fails, move on by setting B A. 2. (3 points) Use loops to count the number of elements of B that are greater than or equal to 5. Name that variable count

Answer 1

CODE :

temp.ру х 1import numpy as np n=5 A np.random.randint(0 10, size (n, n)) np. savetxt('exam2.txt', A, "i', delimiter' np . zero s ( ( n, n), dtypes' int64') 8 #1. Making A equal to B. 10 # readlines is used for reading the whole lines and put it into a list of lines 11 # where each element in the list corresponds to a Line 12F open('exam2.txt').readlines) 13 14 # Enumerate allows us to loop over something and have an automatic counter. 15 for index, item in enumerate(F): 16 17 | #atrip is used to remove spaces and newlines herd and 18 19 B[index] list(map(int, item.stripO.split,) 20 print(B) 21 #map yields a generator. So, we need to convert into list # then 亼plit is used to split by comma separation

ètemp.py x LI 17 18 # trip is used to remove spaces and newlines here and # then split is used to split by comma separation B[index]list (map(int, item.strip).split(') 20 print (B) 21 23 # 2, counting the number of elements greater than 5 24 25 # initialize count with 0 26 count- 27 #8 is a numpy array. So it has shape property which returns the dimensions of the array 29 #shape [O] ts for row and shape[1] ts for column. 30 #print(8.shape) 31 for i in range(B.shape[0]): 32 for j in range(B. shape[1]): count1 34 35 36 37 print(count) etse: pa亼凸

Output:

e temp.py × 目exam2.txt 1:bash ' +曰 く TERMINAL import numpy as np n=5 A np.random.randint (0, 10, size-(n, n)) np.savetxt('exam2 . txt'. A,"Xİ', delimitera..) B= np . zeros((n, n), dtypes' int64') 1 murky :load-and-match$ python temp. py [[3 946 2] [4 5 23 7] 177 557 [1 459 5] [8 6 150] 4 5 8 9 10 # readlines is used for reading the whole tines and put it into a 11st 11 # where each element in the list corresponds to a line 12fopen('exam2.txt').readlines) 13 14 # Enumerate allows us to loop over something and have an automatic coun 15 for index, item in enumerate(F) 16 17 18 # 1, Making A equal to B COUNT: 15 murky: load_and_match$ # map yields a generator. So, we need to convert into list # strip is used to remove spaces and newlines here and # then split ts used to split by comma separation B[index]list(map(int, item.strip().split(","))) 20 print (B) 21 23 # 2, counting the number of elements greater than 5 25 #intttalize count with 26 count=0 27

exam2.txt

temp.py exam2.txt x L2TERMINAL :bash 9,4,6,2 2 4,5,2,3,7 7,7,5,5,7 4 1.4,5,9,5 5 8,6,1,5,0 murky :load-and-match$ python temp. py [3 94 6 2] [4 5 23 7 17755 7] [145 9 5] [8 6 15 0]] COUNT: 15 murky : load_and_match$

#Look out for the indentation and free feel to ask anything.

CODE:

import numpy as np
n = 5
A = np.random.randint(0, 10, size=(n, n))
np.savetxt('exam2.txt', A, '%i', delimiter=',')
B = np.zeros((n, n), dtype='int64')

################################################################################
# 1. Making A equal to B.

# readlines is used for reading the whole lines and put it into a list of lines
# where each element in the list corresponds to a line
f = open('exam2.txt').readlines()

# Enumerate allows us to loop over something and have an automatic counter.
for index, item in enumerate(f):
    # map yields a generator. So, we need to convert into list.
    # strip is used to remove spaces and newlines here and
    # then split is used to split by comma separation.
    B[index] = list(map(int, item.strip().split(',')))
print(B)

#################################################################################
# 2. Counting the number of elements greater than 5

# initialize count with 0
count = 0

# B is a numpy array. So it has shape property which returns the dimensions of the array
# shape[0] is for row and shape[1] is for column.
# print(B.shape)
for i in range(B.shape[0]):
    for j in range(B.shape[1]):
        if B[i][j] >= 5:
            count += 1
        else:
            pass
print("COUNT: ", count)

-------------------------------------------------------------

exam2.txt

3,9,4,6,2
4,5,2,3,7
7,7,5,5,7
1,4,5,9,5
8,6,1,5,0