Question
Given the formula of the kinetic energy of a particle m with
speed v:
KE = 1⁄2mv2 ,
and the formula of the gravitational potential energy:
PE = -GMEm/R,
where G is gravitational constant and ME and R=6378 km are the mass and the radius of Earth. Now the particle is shot from Earth surface to space. Find the minimum required initial speed for this particle to completely escape the influence of Earth gravity (i.e. PE=0). Notice that the gravitational acceleration on Earth surface is g=GME/R2=9.8m/s.

3. Given the formula of the kinetic energy of a particle m with speed v: KE = {mv2, and the formula of the gravitational pote
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Answer #1

Date:...... = Imuz 2 Kinetic energy Potential Energy -GMEM R ME Mass of caille R = Radius of caille 6378 km g = GME 9.8 m/s²conservation of energy was used.

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