It may be obseved that (3,-4,2)T = 1(3,-4,2)T+0(3,-3,3)T. Hence x = (1,0)T.
Also, (3,-3,3)T = 0(3,-4,2)T+0(3,-3,3)T . Hence y = (0,1)T
and (6,-7,5)T =1(3,-4,2)T1(3,-3,3)T. Hence z = (1,1)T
For the matrix A-1-4-3 2 3) consider the set 2 S-b E Rb-Ax for some xE...
If S= {e*, e*, xe* is a fundamental solution set for the homogenous differential equation with constant coefficients dy a2 dy +a dx2 d y + a y 0, dx dx find the values of a ,i= 0, 1, 2, 3 (5 markah/marks) Dengan nilai yang diperolehi dari (a), selesaikanlah masalah nilai awal yang berikut: (b) day 2 (1+2e) d2 y a a dx dy ax a ax dengan 0)1,y' (0)- 2,y (0)-3. By using the values obtained in (a),...
a. Every matrix equation Ax b corresponds to a vector equation with the same solution set. Choose the correct answer below. O A. False. The matrix equation Ax-b does not correspond to a vector equation with the same solution set. O B. False. The matrix equation Ax b only corresponds to an inconsistent system of vector equations. O c. True. The matrix equation Ax-bis simply another notation for the vector equation x1a1 + x2a2 +·.. + xnan-b, where al ,...
Linear Algebra Question: 18. Consider the system of equations Ax = b where | A= 1 -1 0 3 1 -2 -1 4 2 0 4 -1 –4 4 2 0 0 3 -2 2 2 and b = BENA 1 For each j, let a; denote the jth column of A. e) Let T : Ra → Rb be the linear transformation defined by T(x) = Ax. What are a and b? Find bases for the kernel and image...
(5) Consider the 3 x 3 matrix A = 1-ovyT where the vector E R, 1 is the identity matrix and v (a) Determine the eigenvalues and eigenvectors of A. b) Hence find a matrix which diagonalises A. c) For which a is the matrix A singular? (d) For which a is the matrix A orthogonal ? (5) Consider the 3 x 3 matrix A = 1-ovyT where the vector E R, 1 is the identity matrix and v (a)...
Let A = and b = . Show that the equation Ax = b does not have a solution for some choices of b, and describe the set of all b for which Ax = b does have a solution. How can it be shown that the equation Ax = b does not have a solution for some choices of b? A. Row reduce the augmented matrix [A b] to demonstrate that [A b] has a pivot position in every row B. Find a vector...
eclass.srv.ualberta.ca 2 of 2 1. Consider the matrix 3-2 1 4-1 2 3 5 7 8 (a) Find a basis B for the null space of A. Hint: you need to verify that the vectors you propose 20 actually form a basis for the null space. (Recall: (1) the null space of A consists of all x e R with Ax = 0, and (2) the matrix equation Ax = 0 is equivalent to a certain system of linear equations.)...
b. - 2 -1 1 and b Let A = Show that the equation Ax =b does not have a solution for all possible b, and -3 0 3 4-2 2 b3 describe the set of all b for which Ax b does have a solution How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below. O A. Find a vector b for which the...
4. Consider the system y'- Ay(t), for t > 0, with A - 1 -2 (a) Show that the matrix A has eigenvalues וג --1and Az--3 with corresponding eigenvectors u (1,1) and u2 (1,-1) (b) Sketch the trajectory of the solution having initial vector y(0) = ul. (c) Sketch the trajectory of the solution having initial vector y(0) -u2. (d) Sketch the trajectory of the solution having initial vector y(0)-u -u 1 U 4. Consider the system y'- Ay(t), for...
SOLVE ANY (2.b) Pts 15 Suppose A' is any matrix whe row reduced echelon form A Show there is a matris D' Mn a wuch thnt A iDMa such that A I Question 3: The matrix condition B2B Ps 30: In this problen B is n (3.a) Pts 10: If a is an eigenvector for B, what is the attached eigenvalue (3. b) Pts 10: Irge R", why is BU) perpendieular to Bur square, n x n, smmetric matris satisfying...
1-4 - 31 Let A= 3 and b= Show that the equation Ax=b does not have a solution for all possible b, and describe the set 4 26 of all b for which Ax=b does have a solution. How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below. O A. Row reduce the augmented matrix [ a b ] to demonstrate thatſ A b )...