What is the osmolar concentration of a 33% solution of CaCl2?
A solution of 1 mol/L CaCl2 has an osmolarity of 3 Osmol/L (1 mol Ca2+ and 2 mol Cl−).
Molecular mass of CaCl2 is 110.98g/mol per liter
i.e. 11.098g/mol per 100 ml is 1 molar
As per your requirement 33%CaCl2 means 33g/100 ml that produces ~3M CaCl2 solution
Now, 1 mol/L CaCl2 osmolarity is 3 Osmol/L
Then, 3 x 3 = 9 Osmol/L for 33%CaCl2
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