Question

Q2 (10 points): Draw the shear and moment diagram of the beam below. The load distribution varies linearly from 0 kip/ft at Point A to 2.0 kip/ft at Point B and then to 0 kip/ft at Point C. 2 k/ft 4 ft - 12 ft 12 A

Answer 1

Solution A e B * " 12 Reactions {fy =o RBtRc- 1 x 2 x 16 - o RBTRC = 16 kips - Emezo RB X 12 - 4 x 2 x 4 x (12 + 4) - 2 12 + 12 (2+2) = 0 RB = 12.45 kip Re - 3.55 kip from - Sherr Snear Farce Farie Tit t it Sok in AB (a from a Sve =-ų ve ☺ SA (n=o)=0 SB(x=4) = -4 kip s.f. in Bc Infrom as Shi-Pc + 1 uxu : -3.55 + 2 Selu:o) = -3.55 kip SB1M:121= 8.45 kip at sofono Suro -3.55 + 420 Bending moment Иоання Sugging - (u= 6.5344) om C (the sim.) (We 8.m.)

B.m. in AB (In from A) muck X. :-? MA(no) = 0 MB (u=4 ft) = -5.33 kip-ft Bm. in Be (in from c) mu=tReine - I . X = 3:55 - 2 1 2 Me (nao) = MB (4= 12) = -5.33 kip.ft ~ 5.4 k-ft 38 min= 6.53) = 15.45 kip-ft 2° ( parabolic ) 6.53 to 3.55 max = 15.45 k-ft zo (cubic) B MD