Question

A barium hydroxide solution is prepared by dissolving 3.15 g of Ba(OH)2 in water to make 27.4 mL of solution. What is the concentration of the solution in units of molarity?

concentration: M?

If 30.0 mL of the barium hydroxide solution was needed to neutralize a 4.21 mL aliquot of the perchloric acid solution, what is the concentration of the acid?

concentration:

Answer 1

All formula used and solution of problems shown in the following image

# Molat mass of BaloH), =171634 g/mol Igm of BalOH)2 = 3.15 gm. No. of moles = am of compound Imolar mass moles of BaloH) =3.15li41:34= 0.0 1838 moles 11 ml=OiDoll then 22.4 mi= 27.4 Xolool=0.01741 Molarity = No. of moles/ volume of solution in liter. Molasity of Balot) = 0.0183810.0274 = 0.6FM Concentration of Ba(OH2 = 0.671 M # No. of moles = Molarity & Volume of soll in liter Molarity of Ba(OH)2 = 0.671M 1 ml = 0 Doll then 30 ml = 30X0.00150103 liter mole of Ba(OH)2 = 0.671 X 0.03 = 6182013 moles Balanced neutralization reaction is Ba(OH)₂ + 2HClOy - Balclout +2H₂O According to reaction I mole Ba(OH)2 react with a mole con molar retio between Balot) to Haloy is 1:2 therefore to react with 0.02013 mole BalOH)2 required toy = 010201342 = 0.04026 moles Hclou 4.21 m1 = 4.2) Xolool = 0.00421 liteę molarity = No. of moles/volume of solution in liter molarity of Helay = 0.02013 0.0402670.00421 9.563M Concentration of Hcloy = 9.563M