Question 10 of 11 For the galvanic (voltaic) cell Cd2+ (aq) + Fe(s) — Cd(s) +...
For the galvanic (voltaic) cell Cd2+ (aq) + Fe(s) Cd(s) + Fe2+(aq) (E° = 0.0400 V), what is the ratio [Fe2+1/[Cd2+] when E = 0.001 V? Assume T is 298 K 1 2. 3 Х 4 5 6 C 7 8 9 + +/- 0 x 100
Using the Nernst equation calculate the cell voltage for: Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s) when the [Fe2+] = 0.20 M and [Cd2+] = 1.5 M. Potentially useful information: Fe2+ + 2e− → Fe(s); ε0 = -0.44 V Cd2+ + 2e− → Cd(s); ε0 = -0.40 V
Be sure to answer all parts. Consider the following reaction: Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s) E o (Fe2+ / Fe) = −0.4400 V, E o (Cd2+ / Cd) = −0.4000 V Calculate the emf for this reaction at 298 K if [Fe2+] = 0.60 M and [Cd2+] = 0.010 M. E =____ V Will the reaction occur spontaneously at these conditions? yes no cannot predict
Be sure to answer all parts. Consider the following reaction: Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s) E° (Fe2+ / Fe) =-0.4400 V, Eº (Cd2+ / Cd) = -0.4000 V Calculate the emf for this reaction at 298 K if [Fe2+] = 0.85 M and [Cd2+] = 0.010 M. E= Lv Will the reaction occur spontaneously at these conditions? o o yes no cannot predict o
Be sure to answer all parts. Consider the following reaction: Cd(s) + Fe2+(aq) → Cd2+(aq) + Fe(s) e°(Fe2+ / Fe) = -0.4400 V, Eº (Cd2+ / Ca) = -0.4000 V Calculate the emf for this reaction at 298 K if [Fe2+1 0.75 M and Ca2+] = 0.010 M. E- L v Will the reaction occur spontaneously at these conditions? O yes no cannot predict
For a voltaic cell based on the reaction below, what reaction happens at the anode? 2Ni3+(aq)+Cd(s)→2Ni2+(s)+Cd2+(aq) Ni3+(aq)+e-→Ni2+(aq) Ni2+(aq)→ Ni3+(aq)+e- Cd2+(aq)+2e-→Cd(s) Cd(s)→Cd2+(aq)+2e- A student measures the voltage across different metal electrodes placed in a voltaic cell. Using a copper cathode, the voltages when using a first a tin, then gold anode are positive and negative, respectively. The order of chemical reactivity of the solid metals must be Au>Cu>Sn Au=Sn Sn>Cu>Au Au=Sn>Cu
17. Write the overall cell reaction for the following voltaic cell. Cd(s)|Cd2+(aq)||Ni2+ (aq)|Ni(s) 18. Calculate the standard cell potential of the following cell at 25°C. Cd(s) Cd2+ (aq)||Ni2+ (aq) Ni(s)
A voltaic cell that uses the reaction PdCl42−(aq)+Cd(s) → Pd(s)+4Cl−(aq)+Cd2+(aq) has a measured standard cell potential of +1.03 V A. Write the half-cell reaction at the cathode. B. Write the half-cell reaction at the anode
Consider a galvanic cell based on the following two half reactions under standard conditions at 298 K: Fe2+ + 2 e → Fe -0.440 V Cd2+ + 2 e → Cd -0.403 V What will the potential of the cell be when the cathode solution concentration changes by 0.657 M? Cell potential =
1)A voltaic cell operates at 298 K according to the following reaction: 4 Fe2+(aq) + O2 (g) + 4 H+(aq) → 4 Fe3+ (aq) + 2 H2O (l) What is the emf of this cell when [Fe2+] = 6.5908E-4 M, [Fe3+] = 0.699 M, pressure O2 = 0.540 atm and pH = 3.10? 2)A voltaic cell operates at 298 K according to the following reaction: 3 Fe2+(aq) → Fe (s) + 2 Fe3+ (aq) What is the emf of this...