Question

Question 1 The following is the data you will use for this activity. Not yet answered Vol Used Points out of 2.00 3.5 mL Reactants benzonitrile sodium hydroxide (109) Product P Flag 28.6 mL question Exp % Yield benzoic acid 81.6 % Calculate the grams of benzonitrile used. Answer: Question 2 Calculate the moles of benzonitrile used. Not yet answered Points out of 2.00 Answer: Flag question Question 3 Calculate the mass of sodium hydroxide used in grams. Not yet answered Points out of 2.00 Answer: p Flag question Question 4 Calculate the moles of sodium hydroxide used. Not yet answered Points out of 2.00 Answer: p Flag question

Answer 1

C6H&CN +Naon nu a Colgcoon tNH3 + Nall rolume of benzonitrile a 3.5m2 density of benzonitable 1 g/mL. 1 mass - 3.5mixlg 23.59 g's of benzonitrile=3.5g Canswara) moles of benzonitrile = wt = 3.59 melut. To 3. 129/mol (molwt of hensonitrile = 103.12) = 0.634 mol 1. Answer @ ) Answer 3 sodium hydroxide strength = 10% - logm of Naon is dissolved in 100mL 2016 mL will have = 12x 28.6 = 2.869 Naon mol. wt zu Answer y НЕ 2.86 yog/mol mo Naon = О И mol wt =0.0715 mol Answers moles of Contoon formed a moles of CCM, CW used = 0.034 mol ammonent of, CHE COOH = 0.034 X122:12 g 1. = 4.159 Theoretical yield 4.159 Answer & actual yieldin% = 81.6% of 4.15 = 4.15*8116 100 = 3.379.