How many moles of air are in the lungs of a average person with a total lung capacity of 3.8 L? Assume that the person is at 1.0 atm pressure and has a normal body temperature of 37 C
This problem is based on Ideal gas law. Assuming air in lungs behave as an ideal gas we can determine the number of moles.
PV = nRT
n = PV / RT...where P = 1.0atm, V = 3.8L, T = 37oC = 37+273 = 310 K
n = (1*3.8) / (0.08206*310) = 0.15 mole
Thus the number of moles of air in the lungs is = 0.15 mole
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