As we know that the relation between pH and pOH is given by pH + pOH = 14 where pOH is -log[OH-] .
Now the concentration of OH- ion is given in the question I.e., 0.12 M
Now pOH = - log(0.12) = - (- 0.92) = 0.92
Putting the value of pOH in formula of pH we get
pH + 0.92 = 14
pH = 14 - 0.92
pH = 13.08
Please like the answer if this helped. Thank you. :)
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