Question

The reaction shown below has the rate law: Rate = k[BrO3-][Br-][H+]^2.

BrO3-(aq) + 5 Br-(aq) + 6 H+(aq) → 3 Br2(aq) + 3 H2O(l)

What is the order of reaction with respect to Br - ?

Answer 1

Ans :-

The given reaction is :

BrO3-(aq) + 5 Br-(aq) + 6 H+(aq) → 3 Br2(aq) + 3 H2O(l)

Also, given rate law expression of this reaction is :

Rate = k[BrO3-][Br-][H+]2

Where,

k = Rate constant

# Because power of concentration of BrO3- is 1 in rate law expression, therefore order with respect to BrO3- = 1

# Because power of concentration of Br- is 1 in rate law expression, therefore order with respect to Br- = 1

and

# Because power of concentration of H+ is 2 in rate law expression, therefore order with respect to H+ = 2

So, Order of reaction with respect to Br- = 1