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If you can find a plane of symmetry in the flat hexagonal drawing of a substituted...
Make a model of each of the chair conformations of cis-1,2-dibromocyclo- hexane, and show that they...
Make a model of each of the chair conformations of cis-1,2-dibromocyclo- hexane, and show that they are nonsuperimpoasble mirror images of each other. Is cis-1,2-dibromocyclohexane isomer optically active? The planar structure has a plane of symmetry, but the chair conformation doesn't! Yes _No Although each conformer is chiral, the rapid interconversion between the two at room temperature means they cannot be separated. The compound is not chiral. Identifying chirality in cyclohexane derivatives can seem daunting. Fortunately we can greatly simplify...
e. Of course, cyclohexanol never exists in a flat hexagonal form. It is just drawn this...
e. Of course, cyclohexanol never exists in a flat hexagonal form. It is just drawn this way for convenience. It exists in one of two chair conformations that are rapidly interconverting at room temperature, the conformation with the hydroxyl in the equatorial position being favored. Гон — Ян Make a model of cyclohexanol with the OH in the equatorial position. Now do a chair flip, so that the OH is in the axial position. Can you find a plane of...
A. Enantiomers: Certain substances have the unique property of rotating the plane of plane-polarized light. Such...
A. Enantiomers: Certain substances have the unique property of rotating the plane of plane-polarized light. Such light rotation is detectable with the aid of a polarimeter. In order for a molecule to be optically active it must be chiral. Chiral objects lack a plane of symmetry and are non-superimposable on their mirror images. A sp?- hybridized carbon atom can fulfill these requirements if all four of its substituents are different. 1. Methane a) Prepare a methane molecule and then substitute...
4. Absolute Configuration and R/S Sequence Rules. In 3 you constructed models with two stereocenters that...
4. Absolute Configuration and R/S Sequence Rules. In 3 you constructed models with two stereocenters that represented 4 stereoisomers. 2,3-Dibromobutanoic acid exemplifies such a compound, Make models for the isomers of this compound. a. Draw solid/dashed-wedge structures for the 4 possible stereoisomers and label the enantiomers and diastereomers. b. Specify the sequence priority for the substituents on carbon-2 and carbon-3. Label each structure with the proper R/S notation in the drawings above, for example (2R, 35). d. Draw Newman projections...
1. A hydrogen atom in the organic base pyridine, CsHsN, can be substituted by various atoms...
1. A hydrogen atom in the organic base pyridine, CsHsN, can be substituted by various atoms or groups to give XCsH4N, where X is an atom such as Cl or a group such as CH3. The following table gives K, values for the conjugate acids of a variety of substituted pyridines. Atom or Group X (aq) + HCl(aq) → (aq) + Cl-(aq) NO K, of Conjugate Acid 5.9 x 10-2 1.5 x 10-4 6.8 x 10-6 1.0 x 10-6 н....
please explain why the answers are what they are. thank you 18. Which one of these...
please explain why the answers are what they are.
thank you
18. Which one of these molecules does not contain any stereogenic centers? 19. How do the two chemical structures shown in the box below compare to one another? a) They represent the same molecule. b) They are isotopes. (c) They are constitutional isomers. d) They have different chemical formulas. 23. Based on structural characteristics, predict which of these substances has the lowest melting point @woo woo Dance CH 3....
ich has the highest energy? 7. a) Depending upon the kind of models you are using,...
ich has the highest energy? 7. a) Depending upon the kind of models you are using, you may or may not be able to construct models of cyclopropane and cyclobutane. Do so, if possible, but do not break the linkages. Why do we say that these molecules are strained? What is the normal sp3 bond angle? What are the (internal) C-C-C bond angles in cyclopropane? b) Make a model of cyclopentane. Does this molecule seem to have any ring strain...
3. Cyclic compounds The presence of the ring in all but very large ring cyclic molecules...
3. Cyclic compounds The presence of the ring in all but very large ring cyclic molecules prevents full rotation of the ring atoms. For this reason, stereoisomerism may also occur in cyclic molecules. a) Prepare a model of cyclohexane, C6H12. Draw the condensed formula. b) Build a model of methylcyclohexane (C7H14) by replacing one of the hydrogens of cyclohexane with a methyl group. Draw the skeletal formula for methylcyclohexane. 2 c) How many different isomers exist for methylcyclohexane (CyH34)? d)...
3. Diastereomers and Meso Forms. When a molecule has two or more stereogenic centers, stereoisomers that...
3. Diastereomers and Meso Forms. When a molecule has two or more stereogenic centers, stereoisomers that are not mirror images can exist; these are called diastereoisomers. Within this general class, there are special types of stereoisomers that are always optically inactive and are called meso forms. Construct a model with four different colored balls about a carbon center. Construct another identical to the first and verify this by the superimposition test. Now remove the same colored balls, blue (C from...
Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23,...
Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23, 4.24, 4.26 pg 170 - 4.29, 4.31, pg 171-4.36 pg 175 - 4.59 pg 176- 4.74, 4.75, 4.80 pg 177-4.81, 4.82 pg 188- 5.1, 5.4, 5.5, 5.6, 5.11 - Using Table 5.1 pg 198-5.22, 5.25 pg 203 - 5.29 pg 206 - 5.37 pg 209 - 5.39 pg 2.14 5.61 pg 235-6.11, 6.14, 6.16 156 CHAPTER 4 Introduction to Organic Compounds...
Make a model of each of the chair conformations of cis-1,2-dibromocyclo- hexane, and show that they are nonsuperimpoasble mirror images of each other. Is cis-1,2-dibromocyclohexane isomer optically active? The planar structure has a plane of symmetry, but the chair conformation doesn't! Yes _No Although each conformer is chiral, the rapid interconversion between the two at room temperature means they cannot be separated. The compound is not chiral. Identifying chirality in cyclohexane derivatives can seem daunting. Fortunately we can greatly simplify...
e. Of course, cyclohexanol never exists in a flat hexagonal form. It is just drawn this way for convenience. It exists in one of two chair conformations that are rapidly interconverting at room temperature, the conformation with the hydroxyl in the equatorial position being favored. Гон — Ян Make a model of cyclohexanol with the OH in the equatorial position. Now do a chair flip, so that the OH is in the axial position. Can you find a plane of...
A. Enantiomers: Certain substances have the unique property of rotating the plane of plane-polarized light. Such light rotation is detectable with the aid of a polarimeter. In order for a molecule to be optically active it must be chiral. Chiral objects lack a plane of symmetry and are non-superimposable on their mirror images. A sp?- hybridized carbon atom can fulfill these requirements if all four of its substituents are different. 1. Methane a) Prepare a methane molecule and then substitute...
4. Absolute Configuration and R/S Sequence Rules. In 3 you constructed models with two stereocenters that represented 4 stereoisomers. 2,3-Dibromobutanoic acid exemplifies such a compound, Make models for the isomers of this compound. a. Draw solid/dashed-wedge structures for the 4 possible stereoisomers and label the enantiomers and diastereomers. b. Specify the sequence priority for the substituents on carbon-2 and carbon-3. Label each structure with the proper R/S notation in the drawings above, for example (2R, 35). d. Draw Newman projections...
1. A hydrogen atom in the organic base pyridine, CsHsN, can be substituted by various atoms or groups to give XCsH4N, where X is an atom such as Cl or a group such as CH3. The following table gives K, values for the conjugate acids of a variety of substituted pyridines. Atom or Group X (aq) + HCl(aq) → (aq) + Cl-(aq) NO K, of Conjugate Acid 5.9 x 10-2 1.5 x 10-4 6.8 x 10-6 1.0 x 10-6 н....
please explain why the answers are what they are.
thank you
18. Which one of these molecules does not contain any stereogenic centers? 19. How do the two chemical structures shown in the box below compare to one another? a) They represent the same molecule. b) They are isotopes. (c) They are constitutional isomers. d) They have different chemical formulas. 23. Based on structural characteristics, predict which of these substances has the lowest melting point @woo woo Dance CH 3....
ich has the highest energy? 7. a) Depending upon the kind of models you are using, you may or may not be able to construct models of cyclopropane and cyclobutane. Do so, if possible, but do not break the linkages. Why do we say that these molecules are strained? What is the normal sp3 bond angle? What are the (internal) C-C-C bond angles in cyclopropane? b) Make a model of cyclopentane. Does this molecule seem to have any ring strain...
3. Cyclic compounds The presence of the ring in all but very large ring cyclic molecules prevents full rotation of the ring atoms. For this reason, stereoisomerism may also occur in cyclic molecules. a) Prepare a model of cyclohexane, C6H12. Draw the condensed formula. b) Build a model of methylcyclohexane (C7H14) by replacing one of the hydrogens of cyclohexane with a methyl group. Draw the skeletal formula for methylcyclohexane. 2 c) How many different isomers exist for methylcyclohexane (CyH34)? d)...
3. Diastereomers and Meso Forms. When a molecule has two or more stereogenic centers, stereoisomers that are not mirror images can exist; these are called diastereoisomers. Within this general class, there are special types of stereoisomers that are always optically inactive and are called meso forms. Construct a model with four different colored balls about a carbon center. Construct another identical to the first and verify this by the superimposition test. Now remove the same colored balls, blue (C from...
Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23, 4.24, 4.26 pg 170 - 4.29, 4.31, pg 171-4.36 pg 175 - 4.59 pg 176- 4.74, 4.75, 4.80 pg 177-4.81, 4.82 pg 188- 5.1, 5.4, 5.5, 5.6, 5.11 - Using Table 5.1 pg 198-5.22, 5.25 pg 203 - 5.29 pg 206 - 5.37 pg 209 - 5.39 pg 2.14 5.61 pg 235-6.11, 6.14, 6.16 156 CHAPTER 4 Introduction to Organic Compounds...
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