Calculate the pH and pOH for each of the solutions with the following hydrogen ion or hydroxide ion concentrations.
Solution B: [OH–] = 2.56×10-4 M
B)
Given:
[OH-] = 2.56*10^-4 M
use:
pOH = -log [OH-]
= -log (2.56*10^-4)
= 3.592
Given:
pOH = 3.592
use:
PH = 14 - pOH
= 14 - 3.592
= 10.408
Answer:
pH = 10.408
pOH = 3.592
Calculate the pH and pOH for each of the solutions with the following hydrogen ion or...
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