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3) How many grams of K2CO3 would be needed to make 4.55 mL of a 15.00 (m/v) solution?
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Answer #1

Answer:

Given solution is 15 (m/v).

It means 15 g of K2CO3 (solute) in 100 mL of solvent.

Given volume 4.55 mL.

The mass of K2CO3 for 4.55 mL=??

Mass of K2CO3=(4.55 mL x 15 g)/(100 mL)

Mass of K2CO3=0.6825 g.

The mass of K2CO3 would be needed to make 4.55 mL of 15(m/v) solution=0.6825 g.

Please let me know if you have any doubt. Thank you.

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