Question

Constants Periodic Draw all stereoisomers of the structure shown below. There are four possible stereoisomers Interactive 3D display mode CH3 HC Draw the molecules on the caves by choosing buttons from the Tools (for bondel Atoms, and Advanced Template toolbars. The single bond is active by default Show the appropriate stereochemistry by choosing the dashed or wedged buttons and then clicking a bond on the canvas HO delete return 1* Command

Answer 1

This compound contains two chiral center. So total no of stereoisomers is 22 = 4. The trans isomers (2 and 3) are enantiomeric and are therefore different compounds. But, Cis isomers (1 and 4) contains a plane of symmetry. It is superimposable on its mirror image that's why it is a meso compound. So, there for total 3 stereoisomers will be obtained. H3 CH3 H3C, H3C CH3 CH? H3C M не з ----------- - - --- - - - CH₂ Hool meso