Question

A sample of gas in a balloon has an initial temperature of 33 ∘C and a volume of 1.56×103 L . If the temperature changes to 88 ∘C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas? Express your answer with the appropriate units.

Answer 1

Ans: By Solving the problem. Initial Temperature = 33. C = 273 +33 = 306k Final Temperature - 88°C = 273 +88 = 361K And also Initial volume = 1.56 x103L final volume = ? so, Ti = 306K., To = 361K. V = 1.56x103L , Vg = ? Pressure is constant, so, By Charles law. V = V2 or V, T2 = V₂T, By putting the valves 11.56 x103 L X 361 k) = (V2 X 306 K) Vg = 361 X1.56 X103 306 = 563.16 x 1032 306 V2 = 1.84 x 1031 so, New volume V2 = 1.84 X103 L.