A volume of 60.0 mL of a 0.900 M HNO3 solution is titrated with 0.820 M...

Question

Question

A volume of 60.0 mL of a 0.900 M HNO3 solution is titrated with 0.820 M KOH Calculate the volume of KOH required to reach the equivalence point.

Answer 1

Answer #1

HNO, (aq) + KOH(aq) → KNO, (aq) +H,0(1) Concentration of HNO, =0.900 mo! Volume of the HNO, = 60.0 mL X- 1000mL =0.0600L Numb

Answer 2

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