A patient order requires 1.9 L of a 0.5 % benzalkonium chloride antiseptic. You have a...
A patient order requires 1.9 L of a 0.5 % benzalkonium chloride antiseptic. You have a 17 % stock solution. How much stock solution will you need to prepare the order?
Homework Answers
Let of volume of stock solution required be v ml
1.9L=1900 ml
% of stock solution * volume required = % of solution to be made * volume to be made
17 * v = 0.5 * 1900
v = (0.5*1900)/17
v = 55.88 ml
thus , 55.88 ml of stock solution must be dissolved to 1.9L to obtain 0.5% solution.
If you have any query regarding this you may ask in comments.
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