Question

Revie A125" phosphoric acid, H,PO, has the following equilibrium constants H,PO () + H2O(l) = H.PO, ( +H2O(1) HPO," (4) + H2O(1) H,O () + HPO, () H.O( +HPO, (aq) H.O(g) + PO, (n) = = 7.5 x 10-4 6.2 x 10 1.2 x 10-3 Ka Part A What is the pll of a solution of 25 MK,PO, potassium phosphate? Express your answer numerically to the hundredthis place. View Available ) pll-128 ✓ Correct You needed to calcat the for the reaction PO, (g) + HOU) HPO, (g) + OH() And then set up an equation tha t O And the concentration s since they teos the OH-Lyou do Part B What is the pH of a solution of 400 MK,TIPO potassium hydrogen phosh Express you r numerically to the hundredthe place VA ) SAMSUNG logi

For this same problem I need part B and C

thanks!

Answer 1

Kaz = 6.2 X108 - pko - 8- logs 2 = 72 kaz= 4.281513 > Play = 13-10g 7.2 = 12.346 Ka, = 37.5X103 pkg = 3-109 7.5 = 2.125 = 12.38 Part Band " 0.4M ke HPoy ( K₂ upoy - 2K+ + Hpq 2- It is amphiprotic salt. Since to por is involved in 2nd & 3rd dissociation pH = pką + P3 - 7.2 + 12.38 2 I 9.79 Past C: 0. 2M KI,Poy. It is amphiprotic falt; since 1₂ Poy is 1st & 2nd dissociation abo involved in pH = pky + PK₂ = 2.125 + 7.2 4.66