Question

Review Cor pll is a logi concentration s cale used to indicate the hydrogen in of a solution pH = -log H'] The bemperature for each solutions and out of approximately 297 k where - 1.00 x 10 Due to the nation of water, n o us solution, the hydrogen ion concentration and the ronde con concentration OH, B olled to each other by the Ry of water Part A - H l = 10 Lofotion What is the plot the resulting bydrochloric acid solution? where 1.00 x 10 is the value of approximately 207 K. Based on the relation, the pH and pl ease related to each other as 14.00 - pH pOH 0.35 of hydrogen hond is dissolved in water to make Express the pH numerically to two decimal places. View Available Hints) DVD AED OH ? Submit

Answer 1

- part A 0.35g of Hydrogen chloride (Hel) is dissolved in water to make 7.5 L son what is the pH of the resulting Ha soin → As we know that -no of_moles: wt a Moli wt. Molecular wt of ha= 36.46 g/mol wt of Mal = 0.35 g Therefore, No of_moles : 0:35 - 0.00959g_moles - 36.46 As we know that molarity of a soin. is defined as no. of moles of solare present in IL soin since 0.009599 moles of Hc are presentin11 501? many moles in 7.5 L Soin How --SO- - 0.009599 mole 7.5 L XL SMZ Molarity 0001279 mole of Hel soin is 0.001279 m. Trst Scatted-with- CS CamScanner

Molarity of soin (M): 0.001279 moles = Now Mel is a strong acid, which means that it dissociates completely in aqueous soon to produce Hydronium Cations, Hzot Helcagt Hrotes H3ot fags + c cars ... This basically means that every mole of Hydrochloric acid dissolved in water will Produce mole of Hydronium cations Do. of molec of Hz0+ = 0.001297 moles i [H30+] = 0.001297 M PH of soin is cale ulated by taking -log of concentration of Hydronium the cations pH = -109 [ H307] __ :109 [0.00 1297] pH = 2.887 - Hence PH of the solution is - = 2:88 Scanned azith CamScanner

-part 3 - 0.35g of sodium Hydroxide (Maoth) an dissolved in water to make 4SL Solution What is the pH of this solution ? - Ź Wt. of Mact = 0.35g - (given) Mol. wt of NaoH = 40g As we know that no. of moler wt_of_mooth giren - moli wt of Naoh _ = 0.35 40 40 = 0.00875 mol - No.of moles As we know that molarity of a soin is; no. of moles of solute Present in lL Soin .. 0:00875 moleio (naottt 1L soin م عاهم بیان طروی. املاک 4 = 0.00875 mole 4.5lx M = 0.001944 mole_ (M) Molarity of Naoh soin = 0.001944 moles ra Scanned_with_ CamScanner

we know - 5 [01] = 0.001944 As we know that POH = -log[ot] → pol E-log (0.001944) → poH = 2.3113 Therefore, = 2.7113 A - pH +POH = 14 PH 14-2.7 113. - H.2887 . Hence the PH of soin is 11.288 Scanned with CamScanner
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For calculation of pH , molarity of solutions is to be find out , molarit of HCl solution is 0.001279 mole in 7.5 liter ,

And molarity of NaOH solution is 0.001944 mole in 4.5 liter.

For acidic solution ( HCl),we can use the relation

PH = - log ( H3O)+

For basic solution (NaOH ) , we can use the relation

P OH = - log (OH)-

And pH + p OH = 14

From this we calculated the pH of both solutions

For HCl , pH = 2.88

For NaOH , pH = 11.288