Question

Given the thermochemical equations: A(g) ⟶B(g)ΔH=90kJmolB(g) ⟶C(g)ΔH=−140kJmolA(g) ⟶B(g)ΔH=90kJmolB(g) ⟶C(g)ΔH=−140kJmol Find the enthalpy changes for three given...

Given the thermochemical equations:

A(g) ⟶B(g)ΔH=90kJmolB(g) ⟶C(g)ΔH=−140kJmolA(g) ⟶B(g)ΔH=90kJmolB(g) ⟶C(g)ΔH=−140kJmol

Find the enthalpy changes for three given reactions.

3A(g)⟶ 3B(g)3A(g)⟶ 3B(g)

ΔH=ΔH= kJ/mol

B(g)⟶A(g)B(g)⟶A(g)

ΔH=ΔH= kJ/mol

A(g)⟶C(g)A(g)⟶C(g)

ΔH=ΔH= kJ/mol

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Answer #1

Thermochemical Equations ; А(9) » R (7) , ДА = 90 кг /mk. — (а) 3 (7) — e c5), Дң - - 1 чо кт/not – (2) Calculating the entha∆H us an extensive property and can be added , subtracted , multiplied or divided as well .

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Given the thermochemical equations: A(g) ⟶B(g)ΔH=90kJmolB(g) ⟶C(g)ΔH=−140kJmolA(g) ⟶B(g)ΔH=90kJmolB(g) ⟶C(g)ΔH=−140kJmol Find the enthalpy changes for three given...
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