For which of the substances below is AH°F = 0? Multiple Choice N2() O2(g) Na(g) Xe0)
For which of the substances below is AH°f=0? ! Multiple Choice • O2(9) o N2(0) o Na(g) o Хе(1)
In which of the following substances does AHF = 0? . Multiple Choice Ο H2O(1) Ο NaCl(s) Nacis) Ο None of these Ο Br20) Ο O2(g)
2NO(g) ---> N2(g) + O2(8) AH =-180.6 kJ N2(g) +02(g) +C17(9) ---> 2NOC19) AH = +103.4 kJ Find the AH of the following reaction: 2NOCI(9) --->2NO(g) +CH (2)
For which of the substances below is ΔΗ°= 0? Multiple Choice Ο Ο Ο Ο
Calculate AH for the reaction N2H4(0) + O2(g) → N2(g) + 2 H2O(1) given the following data: Equation AH (kJ) 2 NH3(g) + 3 N2O(g) → 4 N2(g) + 3 H2O(l) -1010 N2O(g) + 3 H2(g) → N2H4(1) +H2O(1) -317 2 NH3(g) + 1202(g) → N2H4(1) + H20(1) -143 H2(g) + 1202(g) → H2O(H -286 AH=
1. Which of the following processes is exothermic, given the following: N2(g) + 2 O2(g) + N2O4(1) AH = 9.67 kJ/mol N2(g) + 2 O2(g) + 2 NO2(g) AH = 67.70 kJ/mol A) 2 N2(g) + 4 O2(g) + 2 N204(1) B) 12 N2(g) + O2(g) → % N204(1) C) N2O4(1) + N2(g) + 2 O2(g) D) 2 N2(g) + 4 O2(g) + 2 NO2(g) + N204(1) E) 2 N2(g) + 4 O2(g) → 4NO2(g)
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
Given the standard enthalpy changes for the following two reactions: (1) N2(g) + O2(g) +2NO(g) AH° = 181.8 kJ (2) N2(g) + 202(g)—>2NO2(g) AH° = 66.4 kJ what is the standard enthalpy change for the reaction: (3) 2NO(g) + O2(g) 2NO2(g) AH° = ? Submit Answer Try Another Version 2 item attempts remaining
Given the standard enthalpy changes for the following two reactions: (1) N2(g) + O2(9)— 2NO(g) AH = 181.8 kJ (2) N2(g) +202(9)—2NO29) AH° = 66.4 kJ what is the standard enthalpy change for the reaction: (3) 2NO(g) + O2(9) *2NO2(9) AH° = ? Submit Answer
7) 2 N2(g) + O2(g) → 2 N20(g) AH rxn = + 163.2 kJ a) At 25°C; calculate ASsurr = b) Is ASsys > 0 or < 0? Explain your answer c) Is the reaction spontaneous? AS univ = (ASsurr) + ( ASsys)