Question

Let's say, you did this part of the experiment and you found that for 0.06 grams of unknown acid, you needed 7.85 mL of 0.05M NaOH to reach the equivalence point. Question: How many grams of unknown acid you would need to titrate 25 mL of 0.05 M NaOH? Hint: Use the formula from the lab manual, page 94. (2 points)

Answer 1

Moles of NaOH = 7.85 mL *0.05M = 0.3925 mmol Here 0.3925 mmol NaOH is equivalent to 0.06g of unknown acið, Needed NaOH = 250 ml x0,05M = 1,2500 mmol So, 1.2500 mmol NaOH is equivalent to 0:069 x 1,2500 mmol of aelo 0.3925 mmol = 0.1919 of unknown acið. So, we need 011919 of unknoon acid to Hitrate 25mL of 0.05M ofa Nacht, By another way, 25,0 mL 7.85 mL ancor 0,1919