Question

Nitric oxide (NO) gas partially decomposes into nitrogen (N2) and oxygen (O2) gases after being placed in a closed container.Study the reaction. N2 (8) +202 (8) = 2NO2 (8) What is true about the reaction? O Initially, the rate of the forward reactionStudy the equation. 3A (g) + 4B (g) = 2C(s) + 5D () What is the equilibrium expression for the equation? Or[A]3[B]4 [C]?[D]5

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1.)Rate of reaction is basically how quickly a reaction is proceding. Rate of reaction for 2NO (g) \rightleftharpoons N2(g) + O2(g) is :

R = k[NO]2 , which decreases as reaction proceed. So option D is false.

ICE table:

NO N2 O2
I a 0 0
C -2x +x +x
E a-2x x x

Clearly equlibrium concentration of O2 and NO are not same. So option B is false.

An equlibrium reaction never completes that means after a certain period of time amount of reactant and product becomes constant and does't change. So option C is false.

Rate of forward reaction = Kf[NO]2 , so if we put NO gas initially in the container rate of forward reaction will be maximum. So option A is true.

2. Pure solid and liquid are not included in equilibrium constant expression. This is because they do not effect the reactant amount at equlibrium in the reaction, so they are disregarded and kept at 1.

Given reaction :

3A(g) + 4B(g) \rightleftharpoons 2C(s) +5D(l)

So equlibrium constant expression will be,

K = 1 /[A]3[B]4

3.) As explained in part 1, rate of forward reaction is maximum at the start of the reaction. So option A is false.

At equilibrium, rate of forward reaction becomes equal to rate of backward reaction and hence there is no change is in concentration of reactants or products that does not mean reaction has stopped or chemcial activity has stopped. It only means change in concentration is zero for each compund in the reaction. So option B is false.

A system in  equilibrium is affeccted due to

i) change in temperature of the system

ii) change in concentration of any reactant or product

iii) change in pressure of the system

iv) addition of some inert gas

v) addition of catalyst

Position of equilibrium of don't change over the time. So option C is false.

After equilibrium is attained both forward and backward reaction keeps on going , only concentration change of any reactant or product is zero. So option D is correct.

Please upvote.

Thank you!

Add a comment
Know the answer?
Add Answer to:
Nitric oxide (NO) gas partially decomposes into nitrogen (N2) and oxygen (O2) gases after being placed...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Nitrogen dioxide gas undergoes decomposition producing nitrogen monoxide and oxygen gases: 2 NO2(g)........ 2 NO(g) + O2...

    Nitrogen dioxide gas undergoes decomposition producing nitrogen monoxide and oxygen gases: 2 NO2(g)........ 2 NO(g) + O2(g) A sample consisting of 0.10 moles of NO2 is placed in a 10.0 L in a container that is then heated to 750 K. When equilibrium is reached, the pressure in the container is 0.827 bar. Calculate the equilibrium constant and the degree of dissociation at this temperature. (Hint: pressures are directly proportional to concentration, so they can be used in ICE tables).

  • Nitrogen and oxygen gas react as high temperatures to form nitric oxide, a component of photochemical...

    Nitrogen and oxygen gas react as high temperatures to form nitric oxide, a component of photochemical smog. Net reaction: the net reaction is N2 + O2 --> 2NO Proposed mechanism: O2 <====> 2O   (fast, at equilibrium)                                         N2 + O <-- --> NO + N   (fast, not at equilibrium)                                     N + O2 ----> NO + O    (Slow) a.) Derive the rate law for the proposed mechanism. rate = ____________________________ b.) What is the initial rate law, when very little...

  • Guus Completion Status: QUESTION 3 Nitric oxide reacts with oxygen to form nitrogen dioxide: 2 NOg)...

    Guus Completion Status: QUESTION 3 Nitric oxide reacts with oxygen to form nitrogen dioxide: 2 NOg) + O2(8) = 2 NO268) What is Ke for the forward reaction if the equilibrium concentration of NO is 0.200 M, O2 is 0.100 M, and O 8.00 x 10-2 6.41 10-2 12.5 15.6 QUESTION 4 The equilibrium constant, Ke for the reaction 2 HI(g) = H2(g) +12(g) is 0.0175. What is the equilibrium concentration of HI if the initial concentration of HI is...

  • 7. Gas Law Problem Nitric oxide (NO) reacts with molecular oxygen 2NO(g) + O2(g) → 2NO2(g)....

    7. Gas Law Problem Nitric oxide (NO) reacts with molecular oxygen 2NO(g) + O2(g) → 2NO2(g). Initially, equal volumes of the reactant gases are separated in a 2.0 L container. The pressure of the NO is 1.25 atm, while the pressure of the O2 is 0.85 atm. What are the partial pressures of the gases once the reaction has gone to completion. Assume the temperature remains constant at 0°C.

  • 3. Nitrogen and oxygen react to produce nitric oxide according to the following equation: N2 (g)...

    3. Nitrogen and oxygen react to produce nitric oxide according to the following equation: N2 (g) + O2 (g) → 2 NO (g) The equilibrium constant for this reaction is 1.70 x 10-3. Suppose that 0.280 mol N2 and 0.120 mol O2 are mixed in a 3.00-L reaction vessel. What will be the concentrations of N2, O2, and NO when equilibrium is established? (Hint: assume that the amounts of N2 and O2 that react are small—less than 10% of the...

  • 3. Nitrogen and oxygen react to produce nitric oxide according to the following equation: N2 (g)...

    3. Nitrogen and oxygen react to produce nitric oxide according to the following equation: N2 (g) + O2(g) → 2 NO (g) The equilibrium constant for this reaction is 1.70 x 10-3. Suppose that 0.180 mol N2 and 0.650 mol O2 are mixed in a 4.00-L reaction vessel. What will be the concentrations of N2, 02, and NO when equilibrium is established? (Hint: assume that the amounts of N2 and O2 that react are small-less than 10% of the starting...

  • the reaction between oxygen and nitrogen gases at high temperatures contribute to air pollution: N2(g) +...

    the reaction between oxygen and nitrogen gases at high temperatures contribute to air pollution: N2(g) + O2 = 2 NO ; Kc 1.0*10^-5 at 1500 K ; suppose air has [N2] = 0.080 M and [O2] =0.020 M what is the concentration of NO at equilibrium (do it using small x approximation and don't use quadratic formula)

  • Nitrogen oxide, NO, is a common pollutant produced by the reaction of nitrogen and oxygen gas....

    Nitrogen oxide, NO, is a common pollutant produced by the reaction of nitrogen and oxygen gas. Since these gases are several major components of air, nitrogen oxide forms when air is heated in furnaces, engines and other high temperature combustion reactions. Given the standard enthalpy of formation for NO (g) = 90.25 kJ / mole and using the absolute entropies shown in the table below, the free energy change for the reaction at 25.00 ºC can be calculated, and equals...

  • A sample of gas XY partially decomposes into gases X2 and Y2 in a closed reactor:...

    A sample of gas XY partially decomposes into gases X2 and Y2 in a closed reactor: 2XY = X2 + Y2 Which are true about this system? Select two that apply. At equilibrium, volume is conserved in closed systems. At equilibrium, enthalpy is conserved in closed systems. Energy is not conserved in the system because a closed system allows heat to enter or escape. At equilibrium, mass is conserved in closed systems. Energy is conserved in the system because a...

  • QUESTION 1 (10) Nitric oxide reacts with oxygen to form nitrogen dioxide: 2NO(g) + O2(g) +...

    QUESTION 1 (10) Nitric oxide reacts with oxygen to form nitrogen dioxide: 2NO(g) + O2(g) + 2NO2 (g) a) What is the Kc for the reaction if the equilibrium concentration of NO is 0.300 M, O2 is 0.200 M, and NO2 is 0.530 M at 25°C? b) What is the Kp for the same reaction? c) If the equilibrium re-establishes where [NO]=0.150 M and [02]-0.225 M, what is [NO2) at this point under the same temperature? 2(12) The equilibrium constant...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT