Question

A researcher studying the nutritional value of a new candy places a 5.70 gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.61◦C. If the heat capacity of the calorimeter is 41.70 kJ/K, how many nutritional Calories are there per gram of the candy?Solve: -qrxn= qcalorimeterWhat is the formula for heat (q) for the calorimeter?___________________Did the calorimeter absorb/release heat? Circle your answer.Calculate the energy absorbed by the calorimeter.How many grams of candy was combusted?_____________What is the energy contained in one gram of candy in kJ?_____________________How many kJ are in one Calorie?___________________

Answer 1

SOLUTION whole Given- Heat capacity of calorimeter = 41.70 kJ/k Rise in temperature - 2.61°C or 2.61k of calorimeter i. Total heat absorbed by calorimeter & calorimeter = 41.70+ 2.61 kJ = 108.84 kJ As we know, I calorie = 4.18 J . Calorimeter in calorie - 108.84 kcal ( 4.18 = 26.04 kilocalories i) nutritional calories per gram of candy : - Total energy released - mass of candy unal 26.04 kcal/g 5.70 NOTE - 4.56 kcally By law of calorimetry, total heat gained by calorimeter is equal to the energy released by the candy formula for heat (9) of calorimeter is 9- Heat capacity of calorimeter x Rise of temper 9. CXAT ii)

up the caloximeter absorbed heat as its temperature rise 1 of its temperature fell down then it would have released heat) I Energy absorbed by calarimeter Calorimeter = 108.84 kJ or 26.04 kilocalories as calculated previously ) Energy contained in 1 gram of candy in 108.84 kJ la 7170 ronales 19.09 kJ/g. u. Energy contained in I gram = 19.09 kJ I I calorie has 4.18 J I calorie has 4.18 x 10-3 kJ.
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