I have no clue on how to do this, please help.
I have no clue on how to do this, please help. Consider the following reaction: Cu2+...
Consider the following reaction at 25 °C; Cu2+ (aq) + Fe (s) → Cu (s) + Fe2+ (aq); E0cell = 0.78 V (25 °C) What would be the value of Ecell at 25 °C, if [Fe2+] = 0.40 M and [Cu2+] = 0.040 M.
please show work and how they got the answer 13. If [Cu2+] = 0.30 M for the same cell described below, then what concentration of Fe2+ is needed to result in Ecell = 0.76 V? You will need to use the standard reduction potential table. Cu2+/ Cu → E = +0.34 V Fe2+/ Fe → E = -0.45 Cu?* (aq) + Fe(s) - Fe* (aq) + Cu(s) Eºcell = +0.78 V, Q = x/ 0.30, X = [Fe2+], Using Nernst,...
1- Consider the following redox reaction: Fe(s) + Cu2+(aq) --> Fe2+(aq) + Cu(s) EoCell = 0.78 V If [Cu2+] = 0.3 M, what [Fe2+] is needed so that Ecell = 0.76 V 2- Calculate the Eocell for the following redox reaction: Cu(s) + 2Ag+(aq) --> Cu2+(aq) + 2Ag(s)
26. Determine the redox reaction represented by the following cell notation. Fe(s) I Fe2+(aq) I| Cu2+(aq) I Cu(s) A) Cu(s) + Fe2+(aq) B) Fe(s)+Cu2+(aq) Cu(s)+ Fe2+(aq) C) 2 Fe(s)+ Cu2+(aq)Cu(s) + 2 Fe2+(aq) D) 2 Cu(s) + Fe2+(aq)Fe(s)+ 2 Cu2+(aq) E) 3 Fe(s) + 2 Cu2+(aq) 2 Cu(s)+3 Fe2+(aq) Fe(s) + Cu2+(aq)
3. For the reaction below, what is the value of E when [Cu2+]-0.04 M and [Fe2+]=0.4 M? Cu(aq) + Fe(s)Cu(s) + Fe2 (aq) E +0.78 V 4. How many minutes are required to plate 2.08 g of Cu at a current of 1.26 A? Cu2 (aq) +2e Cu(s)
What is the OH ion concentration in a 4.8 x 10-2 M KOH solution? 2.1 x 10-13 M 4.8 x 10-2 M 1.0 x 10-7 M 4.8 x 10-12 M What is E' for the following balanced reaction? Fe(s) + Cu2+(aq) Fe2+ (aq) + Cu(s) Standard Reduction Potential Half-reaction Fe2+ (aq) + 2e Fe(s) Cu2+ (aq) + 2e Cu(s) -0.44 40.34 O +.010 +0.78 0 -0.78 -0.1
38. The following redox half reactions are combined in a voltaic cell. Which reaction occurs at the cathode and what is the Eceu? Fe2+(aq) + 2e → Fe(s) E°=-0.44 V Cu²+(aq) + 2e → Cu(s) E°= 0.34 V a) b) c) d) Cu2+(aq) + 2e → Cu(s), Ecell = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecel = 0.78 V Fe2+(aq) + 2e → Fe(s), Ecell =-0.10 V Cu²+(aq) + 2e → Cu(s), Ecel = 0.10 V Cu²+ (aq) +...
Consider the following electrochemical cell: Al (s) I Al3+ (aq) (1.00 M) II Cu2+ (aq) (0.0020 M) I Cu (s) where Cu2+ aq + 2e- -> Cu (s) +0.34 V and Al3+ aq + 3e- -> Al (s) -1.66 V Calculate the standard cell potential for the given cell, calculate the cell potential for the given cell, and sketch the electrochemical cell using two beakers and labeling the electrodes, the cathode, the anode, the direction of electron flow in the...
Consider the balanced redox reaction below. 2Hg(I) + 2 Cu2 + (aq) +2CI-(aq)? Hg2CI2(aq) +2 Cu (s) Standard reduction Potentials are given below. Standard Reduction Potentials Reduction Half Reaction Cu2+ (aq) +2e-? Cu (s) 0.34 27 What is the cell potential, Ecell for the following concentrations at 298 K? Cu2+)-0.02M (CI1-0.3M [Hg2Cl21-0.005M Express your answer in units of Volts. 321
Consider a galvanic cell that uses the reaction Cu (s) + 2Fe+ (aq) Cu2+ (aq) + 2Fe+ (aq) Part A What is the potential of a cell at 25 C that has the following ion concentrations? Fel 1 - 1.5x10-4M. Cu2+1 -0.29 M. Fe2+1 -0.18 M Express your answer to two significant figures and include the appropriate units. HA ? Value Units Submit Resvest Answer A galvanie cel has an iron electrode in contact with 0.19 M FeSO, and a...