Question

Complete the following table. (Enter all mass and volume data to the closest 0.01 unit. Enter the concentration of NaOH to 3 significant figures.)

i've got the data down for table one but had no idea how to solve table two, please help

Part A: Titration of vinegar HC2H302(aq) + OH-(aq) → C2H302 (aq) + H20(1) Complete the following table. (Enter all mass and volume data to the closest 0.01 unit. Enter the concentration of NaOH to 3 significant figures.) Data Table A1: Experimental data mass of beaker volume of vinegar mass of beaker + vinegar mass of vinegar Trial 1 49 95.64 4.0 7.10 49) 102.70 49 7.06 Trial 2 g 49) 116.26 ML 4.9 7.00 9 49) 123.07 g 4.) 6.81 ml concentration of NaOH Initial buret reading 4.9 0.498 490.00 49) 12.60 equivalence point buret reading (titrant volume at which pH changes most rapidly) volume of titrant added equivalent point – Initial buret reading M mL 490.00 mL 40) 10.05 mL 4.9) 10.05 mL mL mL) 49) 12.60 Complete the following table. Data Table A2: Calculated results Trial 1 Trial 2 average 4. 94.98 4.0 mmol of NaOH too low too low 4.0 4.0 4.98 mmol of HC2H302 40 too low too low 4.9 mass of HC2H302 x 4.0 too low g too high g molarity of HC2H302 In vinegar x too high g 49 x too low M 40 4.40 % 49) .79 x Check the number of significant figures. M too high M 49 5.40 mass percent of HC2H302 in vinegar 4.9.) 4.90 1 % %

Answer 1

& Concentration of Nath = 0.498 M. volume used: 12.60 ml (Trial 2) mmoles of Natth : 0.498 x 12.60 miles > 6.27 miles. HGH30, in vivegar s: 5.407. (Trial ) as you wrote Mers of HGH302 7.06x Stogas 0.38 gons 1 01

avim I HC H₂O2. 2 mund of wath (0.05+0.04 0.05 monde mour of the Nadh : 3 (6.27+4.98) 25.63mmer mass of HGH302 : 1 (0.38 +0:30) 0.34 grus. nolarity of H₂ H30: 1 (0.89 +0.72) = 0.80 CM)