Solution-
=>0.002 M Ca(OH)2 * (2 mol OH-/1 mol Ca(OH)2) = 0.002 mol OH-
=>-log(OH) = pOH
=>pOH + pH = 14
=>-log(0.004)
= 2.397
=>2.397 + pH = 14
=>pH= 14 - 2.397
=> pH= 11.60
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