Question

Problems 1. MnO4 (aq) + SO32- (aq) → MnO2 (s) + SO42- (aq) in basic solution 2. NO2" (aq) + Al(s) NH3(aq) + Al(OH)4 (aq) in basic solution 3. Mn2+ (aq) + NaBiO3 (s) → Bi* (aq) + MnO4 (aq) + Nat (aq) in acidic solution 4. As2O3 (s) + NO3- (aq) → H3ASO4 (aq) + N2O3 (aq) in acidic solution 5. Pb (s) + PbO2 (s) + H2SO4 (aq) → PbSO4 (s) in acidic solution
How do I solve the following redox reactions? What are the balanced half-reactions? What is the final balanced equation?

Answer 1

Answer ② MnOi (aq) + 50gr (ar) Mu O2 (s) + 504 (an) in basic solution. We have to balanced the above redox rah. In the given reaction, 502² - (aq) oxidised to so4² Card . and Mr OA Laq) reduced to Mr O2 (s). so, the redox half reactions are shown ben - oxidation half-reaction :- 50,2-199) + 20H(aq) → S042709) + H90 +26) • Reduction half - reaction : - Immoj (ar) + 2H₂O + 3ê y MMO2 (s) + 40H-lagu By doing {agh x 3} tegn W x 3} we have 350 (aq) + 60H (ar) 3.50 (aq) + 340 76€ 2 much lam) + 4H20 + 6€" 2 MMO, (s) +80H- (aq) 2MM OA (aq) + 350 (ar) +420 = 2MMO, (s) + 350 (99) + 201 lan) n

ence, the required balanced equation in basic solution is | 2MMOA (aq) + 380 (aq) + H₂O = 2MMO, (ar) + 3 50 lan) e + 204 (ar)