More Practice Balancing Redox Reactions in Acid and Basic Solution
Balance the following redox reaction in both acidic and basic solution using the half reaction method outlined in Recitation 10, Part III.
3. Unbalanced: PbO2(s) + Mn2+(aq) → Pb2+ (aq) + MnO4- (aq)
4. Unbalanced: SO42-(aq) + Cr3+(aq) → SO2(g) + Cr2O72-(aq)
Balance the following redox reaction in both acidic and basic solution using the half reaction method outlined in Recitation 10, Part III.
Balancing Redox Reactions Balance each redox reaction in acidic solution using the half reaction method. H2O2 + Cr2O72- → O2 + Cr3+ TeO32- + N2O4 → Te + NO3- ReO4- +IO- → IO3- + Re
Part IV: Balancing Redox Reactions in Acidic and Basic Solution General rules for balancing redox reactions in acidic or basic solution: 1. Divide the redox reaction into two half-reactions. One that contains the element that gets Oxidized and one that contains the element that gets reduced. 2. Focusing on one half-reaction at a time, balance all non-H and non-0 atoms. 3. Balance the O atoms by adding water molecules to the side with too few oxygens 4. Balance the H...
Balance the following redox equations by the half-reaction method: (a) Mn2+ + H2O2 → MnO2 + H2O (in basic solution) (b) Bi(OH)3 + SnO22− → SnO32− + Bi (in basic solution) (c) Cr2O72− + C2O42− → Cr3+ + CO2 (in acidic solution) (d) ClO3− + Cl− → Cl2 + ClO2 (in acidic solution) (e) Mn2+ + BiO3− → Bi3+ + MnO4− (in acidic solution)
2. Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): MnO (s) + PbO2 (s) → MnO,- + Pb2+ (b) (acid solution): MnO4 + Mn2+ → MnO2 (s) (c) (basic solution): Al (8) + OH → Al(OH) - + H2(g)
balance pls show work its just to check HW12 Balance the following redox in acidic/basic medium MnO- + Fe2+ → Mn2+ + Fe3+ (acidic) Cr2O72- + C,H-OH → Cr3+ + CO2 (acidic) Ag + CN- + 02 → Ag(CN)2- (basic) Cr2O72- + S032– → Cr3+ + SO42- (acidic) C1,02 + H2O2 → C102 +02 (basic) MnO4 + C H204 → Mn2+ + CO2 (acidic) Sn + NO3- → SnC162- + NO2 (basic)
1. Balance the following redox reaction using the method of half-reactions (also called the ion-electron method). Mn2+ (aq) + NaBiO3 (s) → Bi3+ (aq) + MnO4- (aq) + Na+ (aq) 2. Balance the following reaction is basic media. (remember you should have no H+ ions in your final reaction.) Pb(OH)42- (aq) + ClO- (aq) → PbO2 (s) + Cl- (aq)
How do I solve the following redox reactions? What are the balanced half-reactions? What is the final balanced equation? Problems 1. MnO4 (aq) + SO32- (aq) → MnO2 (s) + SO42- (aq) in basic solution 2. NO2" (aq) + Al(s) NH3(aq) + Al(OH)4 (aq) in basic solution 3. Mn2+ (aq) + NaBiO3 (s) → Bi* (aq) + MnO4 (aq) + Nat (aq) in acidic solution 4. As2O3 (s) + NO3- (aq) → H3ASO4 (aq) + N2O3 (aq) in acidic solution...
1. Balance the following reaction in acidic solution. I-(aq) + MnO4-(aq) Mn2+(aq) + I2(s) 2. Write a balanced net ionic equation for the following reaction in basic solution using both methods for balancing a redox reaction: Zn(s) + NO3-(aq) à NH3 (aq) + Zn(OH)42- (aq) 3. Write a balanced net ionic equation for the following reaction in basic solution using both methods for balancing a redox reaction: MnO4-(aq) + C2H5OH(aq) à Mn2+(aq) + HC2H3O2 (aq)
Balance following redox reactions in acidic conditions using the half-reaction method a. Fe + Ag+ → Fe2+ + Ag b. I- + SO42- → H2S + I2 c. Cu + NO3- → Cu2+ + NO2 d. PbO₂ + CI- → Pb2+ + Cl₂
1. (a) Balance the following half-reactions by the ion-electron half-reaction method: (i) (acid solution) HSO3- (aq) → SO42- (aq) (ii) (acid solution) Pu(OH)4 (8) ► Pu+ (aq) (iii) (base solution) CN- (aq) → OCN- (aq) (iv) (base solution) RhO42- (aq) → Rh,03 (s) (b) Which of the above equations are oxidation half-reactions? (c) Give the formulas of the reactants that become oxidized in the course of the reactic Balance the following redox equations by the ion-electron half-reaction method: (a) (acid...