LEFT PLOT : zero order reaction
for zero order reaction the rate law is, [A]t = [A]0 - Kt
so, [A]t Vs t plot will be a straight line with a slope = - K and intercept = [A]0
MIDDLE PLOT : first order reaction
for first order reaction the rate law is, ln [A]t = ln [A]0 - Kt
so. ln [A]t Vs t plot will be a straight line with a slope = - K and intercept = ln [A]0
RIGHT PLOT : second order reaction
for second order reaction the rate law is, 1/[A]t = 1/[A]0 + Kt
so. 1/ [A]t Vs t plot will be a straight line with a slope = K and intercept = 1/ [A]0
Classify each of the following plots based on reaction order. AO In [A] slope =- slope...
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
What is the difference between a first order and a second order reaction? a. For a first order reaction, plotting the natural logarithm of A versus time always gives a straight line with a slope equal to -k For a second order reaction a plot of 1 / A versus time, will produce a straight line with a slope equal to k b. For a first order reaction, plotting the natural logarithm of A versus time always gives a straight...
How do you determine the order of a reaction from a graph? Select one: There is no way to determine reaction order from a graph. Prepare plots of [I/1] vs time and In [I/I] vs time. The value of R2 is the order of the reaction. Prepare a plot of kvs time. The slope of the trendline is the order of the reaction Prepare plots of [I/1] vs time and In [I/I] vs time. Identify which graph has a better...
Complete the table below for zero, first and simple second order reactions 1/[A]- kt + 1/A rate = [A] points mol/L -k In (Al, 1/A -kt + 1/[A] [A] = kt + [Al. k 1AL k (AL, TAI E-k!+ [Alo -k 11AL L2/mois k, In [AL, [Al vs. t rato Al eBook [Al vs. + In (A) vs. rate = kA Print rate 1/[A], vs. -k, [AL L/mols In[A]=kt + In[A]. References Zero Order First Order Second Order Rate law...
5 What are the units of the rate constant (k) for first, second, or zero order reaction? Show how you determined the units of each rate constant. >SO2 + Cla: 6. The following data were obtained at 320°C for the reaction of: SO Cla 0.00 4.00 3,00 2.00 Time, hour 1.00 0.874 [SO Cl), M 0.946 1.024 1,200 1.109 Graph: (a) In [SO Cl2] vs. time Label and attach the graphs to the worksheet. If using Excel, provide the equation...
For the following reaction, K < 1. Classify each of the reactants and products based on their strength as Bronsted Lowry acids or bases. C6H5OH + C17H19O3N yields C6H5O^- + C17H19O3NH^+ Classify based on the following: Stronger Bronsted Lowry acid, Weaker Bronsted Lowry acid, Stronger Bronsted Lowry Base, Weaker Bronsted Lowry Base
For the following reaction, K > 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry acids or bases. (C2H5)3N + HCN→CN- + (C2H5)3NH+
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k 1 ln[A]=−kt+ln[A]0ln[A]=−kt+ln[A]0 ln[A] vs. tln[A] vs. t −k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t k Part A The reactant concentration in a zero-order reaction was 8.00×10−2 MM after 130 ss and 4.00×10−2 MM after 380 ss . What is...
If the reaction Xproducts is second-order, then which of the following graphs is linear with slope +k? versus Rate versus t 1 / [X] versus t [X]2 versus t In [X] versus t
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b. Order Integrated Rate Law Graph Slope 0 [A]=−kt+[A]0[A]=−kt+[A]0 [A] vs. t[A] vs. t −k−k 1 ln[A]=−kt+ln[A]0ln[A]=−kt+ln[A]0 ln[A] vs. tln[A] vs. t −k−k 2 1[A]= kt+1[A]01[A]= kt+1[A]0 1[A] vs. t1[A] vs. t kk A.) The reactant concentration in a zero-order reaction was 0.100 MM after 165 ss and 4.00×10−2 MM after 305 ss . What is the...