Question

using the periodic table to identify the elements with the following electrons configuration

[Ne]3s^1

[Kr] 5s^2 4d^10

[Xe] 5s^2

[Kr] 5s^2 4d^10 5p^3

spell out the full name of the element

Answer 1

[Ne]3s^1 has total 11electrons and belongs to s block and IA groupand 3rd period. It is Na[SODIUM]

[Kr] 5s^2 4d^10This element belongs to 5th period and d-block , as it has 12 valence electrons it belongs to IIB group.

Thus the element is Cd[CADMIUM]

[Xe] 5s^2 This is wrong.

It should be [Xe] 6s2

Then it is Ba[BARIUM] as it belongs to s-block , 6th period with 2 valence electrons( IIA).

[Kr] 5s^2 4d^10 5p^3

this has total 15 valenc electrons , so belongs to 15 group or VA group and 5th period, belongs to p-block.

It is Sb[ANTIMONY]