Question

I need help please: Solubility equilibrium

1. Predict the solubility of each of the following compounds at 25°C. Then determine which of the two compounds in each case is more soluble. Afterward, decide whether you could have determined which of the two compounds was more soluble just by comparing the Ksp values. Explain why or why not. All Ksp values are given at 25°C. a. Magnesium fluoride, MgF2, a compound used to produce lenses in telescopes and other optical devices, has a Ksp value of 5.16 x 10-11 Silver(t) chloride, AgCl, a compound used as an antimicrobial agent in medical supplies, has a Ksp value of 1.77 x 10-10. (3 points)

Answer 1

160) Ksp of magnesium flecoride (Mg) 26.1610-|| at 252 if the solubility of Myf in its saturated solutions be S(M) then the [M924] 2S (M) and (re] 225 (M) Mgf (a) o tomo Mg2+caq) + 2f@caq.) .(Mgetrag)] i Poj= Kep on, S*(25) > Kop one 433 Kepa on S3 4x 8-16 410-4 , 1.29x10-11 - SM (1.29x1024) & ; 2.345x10-4cm) . In the saturated splution of MgF2_at2sc , the solubility of salt Mgf is 2.345x10-4 (M).

| At 25°C temperature, Ksp of Agep o 1.77x105,10, het in a saturated solution of age the solubility of the salt - Agelis S (M) then the concentration of the comresponding of ions will be (Agt] 25 (M) and (ar) 25 (M) Agel (s) + Agt (aq) + Cl - (aq). ta (42) at 250 Agtear]] x [cicom)] = Kep > 1.77x10-10 on, Sxs 1077x10-10 ono, SP 21.77x10-10 as > (1.47X10–1913 > 133x10-5 cm). Now, the solubility of Agee is 1.33x10-5(M) in compare witho Hof which was foemd 2.845*10-46). Therefore due to the highero Sefeibility of Mqf_inaqueous solution than Agel, so mgf will be morre soluble.

ATAZO sca) (6.) The Ksp of calcium iodate, Ca(102)226147x10-6 Let the soleibility of Cal103), in its saturated solution at 25°C be SM). -: [Ca2+] > Ś(M) (10377 25 (1) *". Ca(103) (8) → Calt (aq) + 2103 (aq) Ksp = [cat] [1037 om, Sx(25)"> 6.47x10-6 om, 453, 6:47x10-6 45 (x6:47x10–6)'% (1.618x1000 S 20.0117(M) 1. ^ The solubility of Ca(203)2 is 0.0117(M)

The Kisp value of Barium nitrate, Ba(NO3)2 2 4.64 X20-3 Let the solubility of Ba(NO3), in its saturated solution I be SM). Ba(NO3)₂ (8) Baht (sq) + 2NO3(aq) (Balt] > S(M) ; (NO > 28 (M) - Kap = (Bazt][nost Ooo, Sx(25) 2 4.64x10-3 on, 453 > 4,64x10-3 ris. 9 (1.16*10-34% 30.105(1) Since, the solubility of Ba(NO3)2 = 0.105(M) is highero than that of Ca(103)2 0-0117 (01); So, the compound Ba(NO3)2 will be morre soluble.

In this case we can not directly comment on the solubility of salt on the basis of the just Ksp values. Because the composition of the Salt pairos in (a) combat ao different. (a) Hafy is ao 1:2 type salt (2 anion, Ication) Vs i system Aga is lil type salt (acation, Ianian) 1. So, we can not compare : But in Ca (703), a Vs Ba(NO2), both are 1:2 type salt (reation 2aniaw). Hence here We can predict the solubility of the respectiva salt on the basis of Ksp values Lowers the solubility prooduct value (Ksp), lower will be the solubility of the respective salt and easier to form precipitate in aqueous solution. Kep CCM(703)2) 6.47x10-67 Ksp (Ba(103)) 34064x10-3 - The solubility of Balwoz), will be more