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When an inductor is connected to a 60.0 Hz source it has an inductive reactance of...

When an inductor is connected to a 60.0 Hz source it has an inductive reactance of 54.6 Ω. Determine the maximum current in the inductor (in A) if it is connected to a 45.0 Hz source that produces a 105 V rms voltage.

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Answer #1

Given,

Reactance (xL)=54.6Ω

Frequency (f) = 60 Hz

Voitage ( v ) = 105 V

Frequency( f )= 45 Hz

Find the maximum current in the inductor ( Imax) .

Now ,

Inductor Reactance ( xL ) .

XL = 2πfL

54 .6 = 2π x (60.0 Hz)x L

L = 0.145 H

The maximum current in the inductor .

Imax= √2Vrms/2πfL

=√2*(105V)/2π*(45)(0.145)

= 3.626 A

4 0

> Where does the square root end in the Imax formula?

Zelda1 Sat, Jul 17, 2021 8:14 PM

> I figured it out. It should be sqrt(2) * V/(2*pi*f_2*L).

Zelda1 Sat, Jul 17, 2021 8:18 PM

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