Question

Draw the products of the given reaction. Include all appropriate hydrogen atoms and charges. Draw products. Select Draw Rings More Erase H2C NH2 CH-CH2 + H H3C 1e13 @lale

Answer 1

In our reaction Amine +H₂O as. Me me da una vita + Mic co-wohy ning Me H H : Hao water) Amine 8H lone pair donate - Due to presence of lone part on amines, these act as lewis bases, because Ot donaty lone pair of electrons. Yelectron paio donos) In presence of hao, due to electronegativity differene of oxygen 3-44 and nitrogen 3.04 atom. N– lone papr available for donation and O-H bond $ 700 breakable (due to electronegeti vity clifference ble o and Hydrgan atom Round is a Hts partial charge due electronegativity difference. tell Guculate "ht & csily bond weak. for donation Our At knock out and accepted by Due to whole these upper points amine and act as base- RNHO ta. base aud R-NH₂ R + OH нан

WUUUUUUUUUUUUUUUUUUUUWWWWWWWWWWWWWWWWWWWW As amine au as base and to act as aud (donale Ht). According to Bronsted conjugate acid bode concept. Amide + H20 - Lauborylic aud + ammium ion). Amides au hydroegue in the preunce H+. AS Hao: ů weak nucleophile (nucleust loving having lone pour of electrong) it is not possible for Hyo to attack on Antide asa 20 Anual R-C5NH2 +/Hö: X not possible because Hoo weak nucleophile. - abo (albon cense is weak electrofee- But in the presence of and, mou electrophile centre on cubon atom i produced by protonation Paúdic medium oss because of coton ? auid C- R-Ć - NHg less electron potonation pootonation equiur'n tul charge shift on caebon atom R-G-NH2 on. Oxygen atom because Oxygen having two lone paios Now a havery a ostrong (electrophilll( electront louring) centre. ie easily accept electrons And thö: having two part of electrons attack on electrophilie ocente. as. C (0) 애 OH - Nng trong As On donate R-¢- ühg 7 6) Bora P070) pair to hence pransfer its lone Carbone on Pt. the charge - OH (c) R-CT Thu HT + NH2 t . R-C- o t k DIH Acid

UUUUUWWWWWWWWWWWWWWWWWWWWW WW to Reaction path (6) and (0) - (6) + when two atoms like oxygen and Nitrogen present then 67 Swift to lower clectronegative otom. ie. O N Shift HT (0 pz due to positive charge easily knock down from the molecule. This breakge of bond facelitate by rumoure of it from –OH group of puthis bond automatic break. | NH3 - H - R- & + NH₃ HT ůvabency exceed than 4 Now your given ron. reaction is go amide as do some react Qud act as tt Фон HU Cong= cry & mi-ang +, join yechd-gp-cony N- - heat 1-2: 2 Amide Hechy & N - CH3 OH H₂C-CH -cd -ch Ht transfer — яс си, — — — , OH 43 HT tron HC-L ¢ + HC NH2 + H+ 3 OH come again protonation BAR_Over are re-cu- & -N- che trgonice #z0-cu- & -on + HN o na

Answer 2

1. 

Answer 3

2.