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Consider a mixture of the two solids BaCl2.2H2O (FM 244.26) and KCI (FM 74.551). When the mixture is heated to 160 °C for 1 h

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Answer Given information, A mixture of two solids, Ball2.2H20 = 264.26. KCl : 74.551 The mixture is heated to 160°C for the I= 6.154,103 mass of Bacl-2H20=nXm:wt 2 = 6+15x10 3 X2 44.26 = 1150229. sample (M2). mass of Ra in = Total-mass of Ball ahho =:: hip = 012817 3.784103 74.55 mass of R = 3.78x103.xm.wt -:39) = 0.14759 wt% of K = mass of K - Xloo Total mass wt% of K = 0melo Of Rel present - 3278x103. TneCl = 3.78X10-3 .801 Total moles of a=nitha =1023X10²43.784103 ={ 1.608x10-27 mass of Cl =

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