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Question 15 (2 points) A basic buffer is prepared by adding 0.4870 g of NH4Cl to 1.00 L of 0.2799 M. NH3. Kb (NH3) = 1.8 x 10
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Answer #1

mass of NH₃ cl is 0,4870 g is 53.5 g/mol morar mass of why a more of NMy cl in 0.4870 m Moly 53.5 = 0.00 g 10 mors [NHGC1] =Aslo, Ento] = 0.2799 M pH = pka + log Enth - 9.26 + log (6.2799 ) = 10.7479 0.08910 MANUELINE cs Scanned with the pH in, pha

Hope it helps...pls do upvote

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