Question

Consider the following information:

$2Na(g) + 3N_2(g) \rightarrow 2NaN_3(s)$

The $ΔH^o_{rxn}$ is -87.3 kJ/mol.
The $ΔS^o_{rxn}$ is -344.2 J/mol.
The "per mole" refers to the sodium azide.

Given the above information, answer the questions below. Assume that the system and surroundings are in thermal equilibrium at 298K.

$ΔH^o_{rxn}$ for 2 moles of sodium azide produced is ____ kJ
$ΔS^o_{rxn}$ for 2 moles of sodium azide produced is ____ J/K
$ΔH_{surroundings}$ for the reaction producing 2 moles of sodium azide is _____ kJ
$ΔS_{surroundings}$ for the reaction producing 2 moles of sodium azide is _____ J/K
$ΔS_{universe}$ for the reaction producing 2 moles of sodium azide is ______ J/K
Under these conditions, is the reaction spontaneous?_____ (yes/no)

Unanswered

Answer 1

2 Na(g) + 3N2(3) ► 2N0N3(s) Olloxn = -87:3 kJ/ mol 2 here perfer refers to oson = -344.2 ] mol I the NaN3 =) so for a moles of NaNa oHorn = 2 *(-87-3) - Horn = -174.6 kg . Any osexn = 2*(-344.2) =) osPorn = -688.2 Ilk => OH surrounding = - ohioan OH sur = -6-174-6) Olssy = 174.6 kg ond Assur T-2981 ossur = - oHsuar = 174.681007 - 298 T assum=585.91 J/K Jane

- osniverse = = osan + assum -688.2 + 585.91 o suniverse = -102.29 J/k/ Tove > if anco - then XV reaction will be spontaneous acinion on toso = -174.6 - 298x (-688-2) x 105 ocina = 30.48 KI ouron so so rxh is non-spontaneous in resc Ane