Question

Enter your answer in the provided box. A gas occupying a volume of 692.0 mL at a pressure of 0.828 atm is allowed to expand at constant temperature until its pressure reaches 0.539 atm. What is its final volume?

Answer 1

P1 = Initial pressure = 0.828 atm P2 = Final pressure = 0.539 atm Vi = Initial volume = 692.0 mL V= Final volume

At constant temperature, for a fixed number of moles of an ideal gas,

Pix V = P x V, , - Pixi V, P

Substitute values in above equation

V2 =- P1 x V1 P2 0.828 atm x 692.0 mL 0.539 atm V2 = 1063 L V2 = 1 V2 - 1060 L

Hence, the final volume is approximately 1060 L.