Question

The rate constant of a chemical reaction increased from 0.100.5 to 2.80 s upon raising the temperature from 250 to 30.0 C

Answer 1

Hoe her part By here given, Ke Titial rare constant = 0 al sale constant = 2.80 s? In Chat) . In 2.80 - 2010 in 28 = 3.332 (normal) 0:00 pat parte) we know the formula of activation energy is given by in ) = -EQ Go -).... 0 where, K2 = Final rate constant = 2.80 5! K, Trilial rolle constant = 0.100s! Ea = Activation energy T2 = Final temperature - 39.0°C -139.0 +273) K = 312 K Ti - Initial temperature = 25.0°c (25.0 +273)K = 298 K R = Universal gan constant = 8.319 /molok - now putting the above ralues in equation o we get, 1 in 12.801 = - Ea / L - 1 ) 10.100 / 8.314 Ilmolok ~, 3.332 = - Ea | 298 – 312) K' 8.314 Jl molok ( 92976 ar 3.332 = - Ea 8.314 J/mol 92976 ar, Ea a 3-332 X 8314 x 92976 Ilmoi 312K - X (-14) a. Ea = 183974.5 J/mol .: Ea= 1839745 ks Imar (IS-10SKJJ .. The activation energy of the reaction Ea = 183.3745 kJ/mol (Anner)