Question

18.5 mL of NaOH were required to titrate KHC.H4O4. Set up 3-step stoic concentration of NaOH. to titrate 0.242g of KHPhthalat
UNE 21 Experim CHM 112 Spring 2020 3. Set up 3-step stoichi required 28.4 mL of 0.119 M or the following: If 0.1827 g acid s
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Answer #1

1.Ans :-

No. of moles of KHC8H4O2 = Given mass of KHC8H4O2 in g / Gram molar mass of KHC8H4O2

= 0.242 g / 204.22 g/mol

= 1.185 x 10-3 mol

No. of moles of KHC8H4O2 = No. of moles of NaOH = 1.185 x 10-3 mol

Now,

Molar concentration of NaOH = Moles of NaOH / Volume in L

= 1.185 x 10-3 mol / 0.0185 L

= 0.0640 M

Therefore, required concentration of NaOH = 0.0640 M

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