< Question 20 of 20 > What is the heat of combustion of ethane, C, H,...

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< Question 20 of 20 > What is the heat of combustion of ethane, C, H, in kilojoules per mole of ethane? Enthalpy of formation

Answer 1

Answer #1

Ans :-

Combustion reaction of C2H6 is :

2C2H6 (g) + 7O2 (g) ----------------> 4CO2 (g) + 6H2O (l)

Because,

ΔH0rxn = [Sum of enthalpy of formation of products] - [Sum of enthalpy of formation of reactants]

= [4 x ΔHf0 of CO2 (g) + 6 x ΔHf0 of H2O (l) ] - [ 2 x ΔHf0 of C2H6 (g) + 7 x ΔHf0 of O2 (g)]

= [ 4 x (–393.5 KJ/mol) + 6 x (–285.8 KJ/mol)] - [ 2 x (–84.0 KJ/mol) + 7 x 0.0 KJ/mol]

= [ - 1574 KJ- 1714.8 KJ] - [ - 168 KJ]

= - 3288.8 KJ+ 168 KJ

= - 3120.8 KJ

So, enthalpy of combustion for 2 moles of C2H6 (g) = - 3120.8 KJ

and

Enthalpy of combustion for 1 moles of C2H6 (g) = - 3120.8 KJ / 2 mol = -1560.4 KJ/mol

Therefore, Enthalpy of combustion of C2H6 (g) = ΔH0rxn = - 1560.4 KJ/mol ethane

Answer 2

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