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How many mL (to the nearest mL) of 0.187-M KF solution should be added to 590....

How many mL (to the nearest mL) of 0.187-M KF solution should be added to 590. mL of 0.143-M HF to prepare a pH = 3.90 solution?

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Answer #1

HF is a weak acid having Ka=7.2×10^-4 . (Note: This value of Ka is given in my reference book, if some other value is given in yours then change calculation accordingly)

On Mixing KF in HF solution, it will form acidic buffer solution, For we can apply Henderson equation from there we will get volume of KF solution.

Answer : 2630mL* ka of HF = 7.2x 10-4 salt of WASB) (weak acid + KFF M=0.187M HF + M=0.143M V=590mL Acidic Buffer solution = ? PH_ 3.90 (sal

Please go through attached image for detailed explanation.

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