The given equilibrium reaction is :-
The expression for equilibrium constant of the above equilibrium reaction is shown below as:-
The equilibrium concentration of A, [A] = 0.0657 M
The equilibrium concentration of B, [B] = 0.0750 M
The equilibrium concentration of C, [C] = 0.0256 M
Applying the values in the above equation as:-
Thus, Option A is correct.
Question 4 Look at this system: 2A (g) + B (g) 2C (g) At 300K, equilibrium...
Look at this system: 2A (g) and C (g) + D (g) At 300K, equilibrium is reached, and the concentrations are found to be 0.0824 M A; 0.0946 MC; 0.652 MD What is Kc? 9.08 552 0.00590 3.86 x 106 0.0995 0.00345
Look at this system: 2A (9) mwilio C (g) + D (g) At 300K, equilibrium is reached, and the concentrations are found to be and to 0.0144 MA: 0.0701 M C; 0.860 MD What is Kc? O 5.05 x 10-2 O 2.91 x 103 O 0.990 O 7.06 x 102 O 0.0405 O 9.63
Look at this system: 2A (9) mwibo C (g) + D (9) At 300K, equilibrium is reached, and the concentrations are found to be 0.124 M A; 0.546 M C; 0.0252 MD What is Kc? 44.4 O 30.5 O 0.0190 O 1.86 x 102 0.895 0.00145
Look at this system: 2A (9) + B (9) C (9) + D (9) At 300K, equilibrium is reached, and the concentrations are found to be 0.114 M A; 0.0701 M B; 0.246 M C 0.0352 MD What is Kc? o 9.50 o 335 0.590 o 1.24 x 10-3 e 0.139 0 245 3.05
quick!!!!!!
Given the reaction at 300K: 2A(g) = 3B(g) + C(g) Kc = 5.5 x 10-5. If 12.0 moles of A is added to a 3.0L container (hint, you need molarity not moles in your ICE table), what will the concentration of A be at equilibrium? Neglect x for this problem. Report your answer to 2 significant figures. Answer: 3.8
B. The reaction A(g) + 2B(g) 2C(g) was allowed to come to equilibrium. The initial After the reaction reached equilibrium, the amount of B remaining in the 2.0 L vessel was 1.0 amounts of reactants placed into a 2.00 L vessel were 2,0 mol A and 2.0 mol B and 1,0 mol C. mol of B. Calculate (show formulas and appropriate steps in each case): a) (10 points) Ke for this reaction: Ec = LA)632 (2)(2) = to equilibrium for...
2. For the reaction: A(g) +B(g) = 2C(g) K = 1.0 x 10-5 at 25°C When equilibrium was reached at 25°C, the equilibrium concentrations of the reactant gases were: [A] = 2.5 x10-2M [B] = 2.0 x 10- M Calculate the equilibrium concentration of the product gas C? 3. At a certain temperature the reaction has an equilibrium constant of 0.400. CO(g) + H2O(g) = CO2(g) + H2(g) When 1.50 mol of carbon dioxide gas and 1.50 mol of hydrogen...
A.) Given the reaction 2A + B ⇋ 4 C (all gases) concentrations at equilibrium are A = 0.076 M B = 0.829 M If K = 3.32, find the concentration of C and report it in M units. B.) Cu (s) + 2 Ag+ ⇋ Cu2+ (aq+) + 2 Ag(s) K = 7.88 x 104 PbCl2 (s) ⇋ Pb2+ (aq) + 2 Cl- (aq) K = 2.4 x 10-4 AgI (s) ⇋ Ag+ (aq) + I- (aq) K =...
we - Google Given the following data, determine the rate law for the following reaction 2A+B+2C - products Experiment 2 [A] 0.273 0.819 0.273 0.273 [B] [C] Rate (M/s) 0.763 0.400 3.0 0.763 0.400 9.0 1.526 0.400 12.0 0.763 0.800 4 6.0 Rate = k[A][B][C] Rate = k[A][B][C] Rate = K[A] [B]*C]2 Rate = K[A]2[B] [CH Rate = k[A] [B][C] Question 16 5 pts SOCl2 gas dissociates into SO2 and Cly via the following reaction: SOCI2(e) + SO2(g) + Cl2(8)...