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What mass of aluminum metal can be produced per hour in the electrolysis of a molten aluminum salt by a current of 23 A?! Exp
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Answer #1

From Faraday's first law of electrolysis, the weight of a chemical substance deposited at an electrode is directly proportional to the quantity of electricity passed through the electrolyte.

Q = current (c) in amperes × time (t) in seconds

= 23*1*60*60 = 82800 coulombs

96500 coulombs of charge = 1 faraday

82800 coulombs of charge = 0.8580 faraday

Again, 3 F of electricity produces 27 grams of Aluminium

Therefoe, 0.08580 F of electricity produces (27*0.8580/3) = 7.7 grams of Aluminium

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