Elemental calcium is produced by the electrolysis of molten CaCl2.
A) What mass of calcium can be produced by this process if a current of 6600 A is applied for 50 h? Assume that the electrolytic cell is 66 % efficient.
Express your answer using two significant figures.
*incorrect answer = 8.1 x 10^8 g; 8.6 x 10^8 g
B) What is the minimum voltage needed to cause the electrolysis?
Express your answer using three significant figures.
A)
w = Act / ZF
A = 40.078 g/mol; c = 6600 A; t = 50 h = 180000 s; Z = +2 e-; F = 96485 C/mol of electrons
w = [40.078 g/mol x 6600 A x 180000 s] / [2 e- x 96485 C/mol of electrons] = 246736.093693 g
but cell is 66% efficient = 246736.093693 x (66 / 100) = 162845.821838 g = 1.6 x 105 g
Answer: 1.6 x 105 g
B)
Ca2+(aq) + 2e– → Ca(s) E0red = -2.87 V,
Cl2(g) + 2e– → 2Cl–(aq) E0red = +1.36 V,
E0cell = 1.36 + 2.87 V = 4.23 V
Answer: the minimum voltage needed to cause the electrolysis = 4.23 V
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