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1. What is the mass of He gas when the pressure equals 1.40 atm and the temperature is at 318 K and the volume is 0.214 L?
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P=1.40 atm T= 318K V= 0.214 L. Ideal Gas equation PV = nRT 1.408 0.214 = nxo.08216 318 n= 0.0114 moles. mass of Helium molesPlease like the solution.Feel free to ask any doubt in comments.

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