Question

Consider the following reaction at 298K. Fe2+ (aq) +2 I (aq) → Fe (s) + 12 (s) Which of the following statements are correct?The reduction potential for the following non-standard half cell at 298K is volts. F2 (8.16*10-atm) + 28°—>2F (1.43M) Submi

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Answer #1

Cathode :f 2 2 é fees) Anode : 28 cag) 1₂ (3) the n=2 mol elections E feelife = -0.440 € 12 / 28 = +0.53v Erell = E Cathode -

F₂ (g) +2e af laq) - Een = € -2-303 R 1 log &=2084-2, 303x8.314x24840g. CF/ - 2x G 64850 Pro сец - 87 - 0 29 Су. 80 16810 3 -

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