The reaction A→BA→B has been experimentally determined to be second order. The initial rate is 0.0100 M/sM/s at an initial concentration of AA of 0.100 MM.
Part A
What is the initial rate at [A]=0.400M[A]=0.400M?
What is the initial rate at ?
0.00250 M/sM/s |
0.160 M/sM/s |
0.0100 M/sM/s |
0.0400 M/s |
Since the reaction is 2nd order in A,
Rate law is:
Rate = k [A]^2
So,
Rate2/rate1 = [A]2^2 / [A]1^2
Rate2/0.0100 = (0.400/0.100)^2
Rate2/0.0100 = (4)^2
Rate2/0.0100 = 16
Rate2= 0.160 M/s
Answer: 0.1600 M/s
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