Concentration of NaOH = 0.15M
i,e Molarity of NaOH = 0.15M
Volume of the solution = 1.0L
molar mass of NaOH = 40.0 g/mole
Molarity = number of moles / volume in L
number of moles = Molarity x volume in L
number of moles = 0.15M x 1.0L = 0.15 moles
number of moles of NaOH = 0.15 moles
but, number of moles of NaOH = mass of NaOH / molar mass of NaOH
mass of NaOH = number of moles of NaOH x molar mass of NaOH
mass of NaOH = 0.15 x 40.0 = 6.0 grams
mass of NaOH required = 6.0 grams
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